1. Defining an array (character type) of a size 3 called array
    char [] array = new char[10]
    
  2. Ask user to enter 10 characters and assign each of the characters into the array
    for (int i = 0; i < array.length; i++)
        array[i] = keyboard.next().charAt(0);
    
  3. Use the data in array to reverse a list called reverse so that the first element in the list called array is the last element in reverse
    for (int i = 0; i < array.length; i++)
        reverse[reverse.length – i] = array[i];
    
  4. Write the first use way to use for-loop to print out all elements in the list called reverse
    for (int i = 0; i < reverse.length; i++)
        System.out.print(reverse[i] + “ ” );
    
  5. Write the second use way to use for-loop to print out all elements in the list called reverse
    for (char value : reverse)
        System.out.print(value + “ ” );
    
  6. Define a 3 by 4 floating point values array, called scores
    double [][] scores = new double [3][4];
  7. Assign the value for each cell in the array called scores to columnIndex * 20 / rowIndex
    for (int row = 0; row < scores.length; row++)
        for (int col = 0; col < scores[row].length; col++)
            scores[row][col] = col * 20 / (double) row;
    
  8. Print all the values in the array called scores
    for (int row = 0; row < scores.length; row++) {
        for (int col = 0; col < scores[row].length; col++)
            System.out.print (scores[row][col] + “\t”);
        System.out.println();
    }
    
  9. Write a findMax method which finds the maximum value in the data stored in
    scores

    static double findMax(double [][] scores) {
        double max = scores[0][0];
        for (int row = 0; row < scores.length; row++)
          for (int col = 0; col < scores[row].length; col++)
            if (scores[row][col] > max)
              max = myScores[row][col];
        return max;
    }
    
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About the Author fvcproductions

I like to dabble with things that ought to be dabbled with.

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